On passing -SO-2- gas in acidified -K-2-Cr-2-O-7- solution- green colour is produced due to formation of-Cr-SO-4-K-2-Cr-O-4-Cr-2-SO-4-3-Cr-2-O-3-

Question

Toppr Admin · Accepted Answer

Sulphur dioxide reacts with acidified potassium dichromate to form chromium sulphate - potassium sulphate and water- Potassium dichromateturns golden yellow solution of potassium dichromate green-SO2-K2Cr2O7-x2192-Cr2-SO4-3-K2SO4-H2O

On passing ${S O}_{2}$ gas in acidified $K_{2} {C r}_{2} O_{7}$ solution, green colour is produced due to formation of:
$C r {S O}_{4}$
$K_{2} C r O_{4}$
${C r}_{2} {({S O}_{4})}_{3}$
${C r}_{2} O_{3}$

Sulphur dioxide reacts with acidified potassium dichromate to form chromium sulphate , potassium sulphate and water. Potassium dichromateturns golden yellow solution of potassium dichromate green.
$S O_{2} + K_{2} C r_{2} O_{7} \to C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + H_{2} O$

On passing SO2 gas in acidified K2Cr2O7 solution, green colour is produced due to formation of:CrSO4K2CrO4Cr2(SO4)3Cr2O3

Sulphur dioxide reacts with acidified potassium dichromate to form chromium sulphate , potassium sulphate and water. Potassium dichromateturns golden yellow solution of potassium dichromate green.SO2+K2Cr2O7→Cr2(SO4)3+K2SO4+H2O

On passing ${S O}_{2}$ gas in acidified $K_{2} {C r}_{2} O_{7}$ solution, green colour is produced due to formation of:
$C r {S O}_{4}$
$K_{2} C r O_{4}$
${C r}_{2} {({S O}_{4})}_{3}$
${C r}_{2} O_{3}$

Sulphur dioxide reacts with acidified potassium dichromate to form chromium sulphate , potassium sulphate and water. Potassium dichromateturns golden yellow solution of potassium dichromate green.
$S O_{2} + K_{2} C r_{2} O_{7} \to C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + H_{2} O$