Given,
Time period of SHM is one spring and mass is connected
Spring constant, k
Attached mass, m
So, frequency is, f=2π√km
As in the figure, if another spring is added in parallel.
Both spring identical, new spring constant for two parallel spring.
knew=k+k=2k
Time period of oscillation,
fnew=2π√mknew=2π√m2k
fnew=1√22π√mk=f√2
Hence, new frequency is f√2