Question

On the sides AB and AC of triangle ABC, equailateral triangle ABD and ACE are drawn, then $\angle CAD=\angle BAE$
If true then enter $1$ and if false then enter $0$

Answer 1

Given: $△$s ABD and CAE are equilateral triangles.
$\angle CAD=\angle CAB+\angle BAD$
$\angle CAD=\angle CAB+60$ (I)
$\angle BAE=\angle BAC+\angle CAD$
$\angle BAE=\angle BAC+60$ (II)
Thus, from I and II
$\angle CAD=\angle BAE$ ($\angle BAC=\angle CAB$ (Common angles))