One mole of an ideal monoatomic gas is mixed with $1$ mole of an ideal diatomic gas. The molar specific heat of the mixture is:

Question

One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas- The molar specific heat of the mixture is-8 cal3 cal9 cal4 cal

Toppr Admin · Accepted Answer

Cv-32R-xA0- - for monoatomic-Cv-52R-xA0- - for diatomic-Thus for mixture-Cv-32R-52R-2-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0- -xA0- -xA0- -xA0-2R-2-xD7-2-xA0-cal-xA0- -xA0- -xA0- -xA0-4-xA0-calHence- the correct answer is option D-

One mole of an ideal monoatomic gas is mixed with $1$ mole of an ideal diatomic gas. The molar specific heat of the mixture is:
$8 c a l$
$3 c a l$
$9 c a l$
$4 c a l$

$C_{v} = \frac{3}{2} R$ ( for monoatomic)

$C_{v} = \frac{5}{2} R$ ( for diatomic)

Thus for mixture:

$C_{v} = \frac{[\frac{3}{2} R + \frac{5}{2} R]}{2}$

$= 2 R = 2 \times 2 c a l$

$= 4 c a l$

Hence, the correct answer is option D.

One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas. The molar specific heat of the mixture is:8 cal3 cal9 cal4 cal

Cv=32R ( for monoatomic)Cv=52R ( for diatomic)Thus for mixture:Cv=[32R+52R]2 =2R=2×2 cal =4 calHence, the correct answer is option D.

One mole of an ideal monoatomic gas is mixed with $1$ mole of an ideal diatomic gas. The molar specific heat of the mixture is:
$8 c a l$
$3 c a l$
$9 c a l$
$4 c a l$

$C_{v} = \frac{3}{2} R$ ( for monoatomic)

$C_{v} = \frac{5}{2} R$ ( for diatomic)

Thus for mixture:

$C_{v} = \frac{[\frac{3}{2} R + \frac{5}{2} R]}{2}$

$= 2 R = 2 \times 2 c a l$

$= 4 c a l$

Hence, the correct answer is option D.