Overleftrightarrow-AB- - overleftrightarrow-CD- in the following figure- overleftrightarrow-XY- is the transversal- If m angle PQA - 140-o- the measure of remaining angles-

Question

Toppr Admin · Accepted Answer

M-x2220-XPC-140o- m-x2220-DPQ-140o- m-x2220-BQY-140o- m-x2220-AQY-40o- m-x2220-PQB-40o- m-x2220-CPQ-40o- m-x2220-XPD-40o-

$\leftarrow \to A B$ || $\leftarrow \to C D$ in the following figure. $\leftarrow \to X Y$ is the transversal. If $m ∠ P Q A = 140^{o}$ , find the measure of remaining angles:

$m ∠ X P C = 140^{o}$ , $m ∠ D P Q = 140^{o}$ , $m ∠ B Q Y = 140^{o}$ , $m ∠ A Q Y = 40^{o}$ , $m ∠ P Q B = 40^{o}$ , $m ∠ C P Q = 40^{o}$ , $m ∠ X P D = 40^{o}$ .

←→AB || ←→CD in the following figure. ←→XY is the transversal. If m∠PQA=140o, find the measure of remaining angles:

m∠XPC=140o, m∠DPQ=140o, m∠BQY=140o, m∠AQY=40o, m∠PQB=40o, m∠CPQ=40o, m∠XPD=40o.

$\leftarrow \to A B$ || $\leftarrow \to C D$ in the following figure. $\leftarrow \to X Y$ is the transversal. If $m ∠ P Q A = 140^{o}$ , find the measure of remaining angles:

$m ∠ X P C = 140^{o}$ , $m ∠ D P Q = 140^{o}$ , $m ∠ B Q Y = 140^{o}$ , $m ∠ A Q Y = 40^{o}$ , $m ∠ P Q B = 40^{o}$ , $m ∠ C P Q = 40^{o}$ , $m ∠ X P D = 40^{o}$ .