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Question

Oxidation number of 'S' in Na2S4O6 is:
  1. +0.5
  2. 2.5
  3. +4
  4. +6

A
+6
B
2.5
C
+4
D
+0.5
Solution
Verified by Toppr

Let the oxidation number of S in Na2S4O6 be x. The oxidation states of Na and O are +1 and 2 respectively. Since the atom as whole is neutral, following equation holds true:
2×(+1)+4×(x)+6×(2)=02+4x12=04x=1224x=10x=52=2.5

Hence, answer is B.

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