Question

$p$ is six times as large as $q.$ The percent that $q$ is less than $p$ is

• A. $83\frac{1}{3}$
• B. $63\frac{1}{3}$
• C. $70$
• D. $50$

Answer 1

Answer: (A)

The correct option is A $83\frac{1}{3}$
Given, $p=6q$
$\therefore$ Required per cent
$=\left(\frac{p-q}{p}\right)\times 100\%$ $=\left(\frac{6q-q}{6q}\right)\times 100\%$
$=(\frac{5q}{6q}\times 100)\%$ $=-\frac{250}{3}\%$ $=83\frac{1}{3}\%$