P-4-5- and Q-5-8- are the endpoints of a line segment PQ- The ratio in which PQ is divided by the y-axis is3-24-5 externally4-5 Internally5-8 externally

Question

Toppr Admin · Accepted Answer

Let PQ intersects the y-axis at A Then the x-coordinate of A is 0
Let PA :AQ be m : 1 Then by Section Formula,

x-coordinate of $P = \frac{(m) (5) + (1) (4)}{m + 1}$
or 5m +4 = 0 or $m = - \frac{4}{5}$
Since m is negative the division is external, the ratio being 4 :5

P(4,-5) and Q(5,8) are the endpoints of a line segment PQ. The ratio in which PQ is divided by the y-axis is3:24:5 externally4:5 Internally5:8 externally

Let PQ intersects the y-axis at A Then the x-coordinate of A is 0Let PA :AQ be m : 1 Then by Section Formula,x-coordinate of P=(m)(5)+(1)(4)m+1or 5m +4 = 0 or m=−45Since m is negative the division is external, the ratio being 4 :5

P(4,-5) and Q(5,8) are the endpoints of a line segment PQ. The ratio in which PQ is divided by the y-axis is
3:2
4:5 externally
4:5 Internally
5:8 externally

Let PQ intersects the y-axis at A Then the x-coordinate of A is 0
Let PA :AQ be m : 1 Then by Section Formula,

x-coordinate of $P = \frac{(m) (5) + (1) (4)}{m + 1}$
or 5m +4 = 0 or $m = - \frac{4}{5}$
Since m is negative the division is external, the ratio being 4 :5