Percentage of sodium sulphate -Na-2SO-3- in hydrated salt is 50- Hence- molecular formula of hydrated salt is Na-2S-2O-3cdot 7H-2O-If true enter 1- else enter 0-

Question

Toppr Admin · Accepted Answer

Molar mass of-xA0-Na2S2O3-126gmol-x2212-1Given- it is 50- by mass- So-xA0-Mass of water molecules -126gNumber of moles of water -12618-7So- compound is-xA0-Na2S2O3-x22C5-7H2O-

Percentage of sodium sulphate $(N a_{2} S O_{3})$ in hydrated salt is $50$ . Hence, molecular formula of hydrated salt is $N a_{2} S_{2} O_{3} \cdot 7 H_{2} O$ .
If true enter 1, else enter 0.

Molar mass of $N a_{2} S_{2} O_{3} = 126 g m o l^{- 1}$
Given, it is $50$ % by mass. So,
Mass of water molecules $= 126 g$
Number of moles of water $= \frac{126}{18} = 7$
So, compound is $N a_{2} S_{2} O_{3} \cdot 7 H_{2} O$ .

Percentage of sodium sulphate (Na2SO3) in hydrated salt is 50. Hence, molecular formula of hydrated salt is Na2S2O3⋅7H2O.If true enter 1, else enter 0.

Molar mass of Na2S2O3=126gmol−1Given, it is 50% by mass. So, Mass of water molecules =126gNumber of moles of water =12618=7So, compound is Na2S2O3⋅7H2O.

Percentage of sodium sulphate $(N a_{2} S O_{3})$ in hydrated salt is $50$ . Hence, molecular formula of hydrated salt is $N a_{2} S_{2} O_{3} \cdot 7 H_{2} O$ .
If true enter 1, else enter 0.

Molar mass of $N a_{2} S_{2} O_{3} = 126 g m o l^{- 1}$
Given, it is $50$ % by mass. So,
Mass of water molecules $= 126 g$
Number of moles of water $= \frac{126}{18} = 7$
So, compound is $N a_{2} S_{2} O_{3} \cdot 7 H_{2} O$ .