Perimeter of triangle ABC is 14cm- AB-4-5 cm and angle A - 80-o- Construct triangle ABC-

Question

Toppr Admin · Accepted Answer

1- Draw AB- 4-5 cm-xA0-2- Draw angle 80 deg at A and cut an arc of AD- 9-5 cm- -14- 4-5 - 9-5-3- Join BD-4- Draw perpendicular bisector of BD which meets AD at C-5- Join BC-xA0-ABC is the required triangle-

Perimeter of $△ A B C$ is 14cm, AB=4.5 cm and $∠ A = 80^{o}$ . Construct $△ A B C$ .

1. Draw AB= 4.5 cm
2. Draw angle 80 deg at A and cut an arc of AD= 9.5 cm. (14- 4.5 = 9.5)
3. Join BD.
4. Draw perpendicular bisector of BD which meets AD at C.
5. Join BC
ABC is the required triangle.

Perimeter of △ABC is 14cm, AB=4.5 cm and ∠A=80o. Construct △ABC.

1. Draw AB= 4.5 cm 2. Draw angle 80 deg at A and cut an arc of AD= 9.5 cm. (14- 4.5 = 9.5)3. Join BD.4. Draw perpendicular bisector of BD which meets AD at C.5. Join BC ABC is the required triangle.

Perimeter of $△ A B C$ is 14cm, AB=4.5 cm and $∠ A = 80^{o}$ . Construct $△ A B C$ .

1. Draw AB= 4.5 cm
2. Draw angle 80 deg at A and cut an arc of AD= 9.5 cm. (14- 4.5 = 9.5)
3. Join BD.
4. Draw perpendicular bisector of BD which meets AD at C.
5. Join BC
ABC is the required triangle.