Photons of energy 5 eV are incident on the cathode. Electrons reaching the anode have kinetic energies varying from 6 eV to 8 eV. Find the work function of the metal and state whether the current in the circuit is less than or equal to saturation current in eV.
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Solution
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According to Einstein's equation
K.E=hν−hν0
So, K.Emax=(5−ϕ)eV
When these electrons are accelerated through 5V, they will reach the anode with maximum energy=(5−ϕ+5)eV
∴10−ϕ=8
ϕ=2eV
Current is less than saturation current because if slowest electron also reaches the plate it would have 5eV energy at the anode, but it is given that the minimum energy is 6eV, So current in the circuit is less than the saturation value
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