For the 4-bus system, containing transmission lines and transformers. The admittance matrix is

Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 60 & j 40 & 0 0 & j 40 & - j 60 & j 20 0 & 0 & j 20 & - j 25 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

If a transmission line having

π

-equivalent circuit as shown below is connected between

2^{n d}

and

4^{t h}

buses. Then the modified

Y_{b u s}

matrix will be

Where,

Z_{s e}

= series impedance of transmission line.

Y_{s h} =

shunt admittance of transmission line.

$Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 50 & j 40 & 0 0 & j 40 & - j 60 & j 20 0 & 0 & j 20 & - j 15 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦$
$Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 50 & j 40 & 0 0 & j 40 & - j 60 & j 20 0 & - j 20 & j 20 & - j 15 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦$
$Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 50 & j 40 & - j 20 0 & j 40 & - j 60 & j 20 0 & - j 20 & j 20 & - j 15 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦$
$Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 40 & j 40 & - j 20 0 & j 40 & - j 60 & j 20 0 & - j 20 & j 20 & - j 5 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦$

Physical path between transmitter and receiver in a data transmission system is known as:Transmission mediaSignalBandwidthBandlength

Physical path between transmitter and receiver in a data transmission system is known as:
Transmission media
Signal
Bandwidth
Bandlength