Planck-s constant has the dimensions as that of-Linear momentumEnergyAngular momentumPower

Question

Toppr Admin · Accepted Answer

Plank-apos-s-xA0-constant -ML2T-x2212-1Energy -M1L2T-x2212-2Power -M1L2T-x2212-3Linear momentum-xA0-MLT-x2212-1Angular momentum -ML2T-x2212-1Hence- option D is correct-

Planck's constant has the dimensions as that of:
Linear momentum
Energy
Angular momentum
Power

Plank's constant $= M L^{2} T^{- 1}$
Energy $= M^{1} L^{2} T^{- 2}$
Power $= M^{1} L^{2} T^{- 3}$
Linear momentum $= M L T^{- 1}$
Angular momentum $= M L^{2} T^{- 1}$
Hence, option D is correct.

Planck's constant has the dimensions as that of:Linear momentumEnergyAngular momentumPower

Plank's constant =ML2T−1Energy =M1L2T−2Power =M1L2T−3Linear momentum =MLT−1Angular momentum =ML2T−1Hence, option D is correct.

Planck's constant has the dimensions as that of:
Linear momentum
Energy
Angular momentum
Power

Plank's constant $= M L^{2} T^{- 1}$
Energy $= M^{1} L^{2} T^{- 2}$
Power $= M^{1} L^{2} T^{- 3}$
Linear momentum $= M L T^{- 1}$
Angular momentum $= M L^{2} T^{- 1}$
Hence, option D is correct.