Point charges q,−q,2Q and Q are placed in order at the corners A,B,C,D of a square of side 2b. If the field at the midpoint CD is zero, then qQ is:
2
2√25
5√52
1
A
5√52
B
1
C
2√25
D
2
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Solution
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Point charges q, −q, 2Q and Q are placed in order to the corners. Here, four point charges +q, 2Q, −q, Q are given along with diagonal side.
√(2b)2+(2b)2
=√4b2+4b2
=√8b2
=b√4×2
=2b√2
Now, the electric field at the intersection point of the diagonals of the square. Hence, the net electric field.
E=K(q+2Q−q+Qr2)
=3Qr2K
=9×109×3×Q2b√2
=5√52
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