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Positive and negative point charges of equal magnitude are kept at (0,0a2) and (0,0−a2) respectively. The work done by the electric field when another positive point charge is moved from (−a,0,0) to (0,a,0) is :
- positive
- zero
- depends on the path connecting the initial and final positiions
- negative
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Solution
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The charges make an electric dipole. A and B points lie on the equitorial plane of the dipole. Therefore potential at A= potential at B
W=Q(VA−VB)=q×0=0
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