Question

Potential difference between the points P and Q in the electric circuit shown is

• A. 4.5 V
• B. 1.2 V
• C. 2.4 V
• D. 2.88 V

Answer 1

Answer: (D)

In the given circuit, current flowing through 3 ohm resistor is parallel to the resistances in either sides of branch PQ.

Hence, equivalent resistance $R_{eq}$, is

$\frac{1}{R_{eq}}=\frac{1}{8}+\frac{1}{3}+\frac{1}{16}$

$\frac{1}{R_{eq}}=\frac{1}{3}+\frac{3}{16}$

$R_{eq}=\frac{16\times 3}{25}$

$\therefore V_P-V_Q=i{R}_{eq}=1.5\times \frac{16\times 3}{25}=2.88volt.$