PQ - BRIf the above statement is true then mention answer as 1- else mention 0 false-

Question

Toppr Admin · Accepted Answer

Given- ABCD is a square-thus- AB-BCAP-BQ -Given-AB-x2212-AP-BC-x2212-BQPB-CQ -I-Now- In -x25B3-PBQ and -x25B3-CQR-x2220-PBQ-x2220-QCR -Each 90-x2218-PB-CQ -From I-BP-CR -Given-thus- -x25B3-PBQ-x2245-x25B3-CQR -SAS rule-or- PQ-QR -By cpct-

PQ = BR
If the above statement is true then mention answer as 1, else mention 0 if false.

Given: ABCD is a square.
thus, $A B = B C$
$A P = B Q$ (Given)
$A B - A P = B C - B Q$
$P B = C Q$ (I)
Now, In $△ P B Q$ and $△ C Q R$ ,
$∠ P B Q = ∠ Q C R$ (Each $90^{\circ}$ )
$P B = C Q$ (From I)
$B P = C R$ (Given)
thus, $△ P B Q ≅ △ C Q R$ (SAS rule)
or, $P Q = Q R$ (By cpct)

PQ = BRIf the above statement is true then mention answer as 1, else mention 0 if false.

Given: ABCD is a square.thus, AB=BCAP=BQ (Given)AB−AP=BC−BQPB=CQ (I)Now, In △PBQ and △CQR,∠PBQ=∠QCR (Each 90∘)PB=CQ (From I)BP=CR (Given)thus, △PBQ≅△CQR (SAS rule)or, PQ=QR (By cpct)

PQ = BR
If the above statement is true then mention answer as 1, else mention 0 if false.

Given: ABCD is a square.
thus, $A B = B C$
$A P = B Q$ (Given)
$A B - A P = B C - B Q$
$P B = C Q$ (I)
Now, In $△ P B Q$ and $△ C Q R$ ,
$∠ P B Q = ∠ Q C R$ (Each $90^{\circ}$ )
$P B = C Q$ (From I)
$B P = C R$ (Given)
thus, $△ P B Q ≅ △ C Q R$ (SAS rule)
or, $P Q = Q R$ (By cpct)