PQRS is a parallelogram- QM is the height from Q to SR and QN is the height from Q to PS- If SR -12 cm and QM -7-6 cm Find QN- PS -8 cm-

Question

Toppr Admin · Accepted Answer

Given- SR-12-cm- QM-7-6-cm- PS-8-cm-Area of parallelogram-base-times-height-12-times 7-6-91-2cm-2-Area of parallelogram-base-times-height-Rightarrow 91-2-8-times-QN-Rightarrow QN-dfrac-91-2-8-11-4-cm-

PQRS is a parallelogram. QM is the height from Q to SR and QN is the height from Q to PS. If SR $$=12\ cm$$ and QM $$=7.6\ cm$$ Find QN, if PS $$=8\ cm.$$

Given: SR$$=12$$cm, QM$$=7.6$$cm, PS$$=8$$cm.

Area of parallelogram$$=$$base$$\times$$height
$$=12\times 7.6=91.2cm^2$$.

Area of parallelogram$$=$$base$$\times$$height
$$\Rightarrow 91.2=8\times$$QN
$$\Rightarrow QN=\dfrac{91.2}{8}=11.4$$cm.

PQRS is a parallelogram. QM is the height from Q to SR and QN is the height from Q to PS. If SR $$=12\ cm$$ and QM $$=7.6\ cm$$ Find QN, if PS $$=8\ cm.$$

Given: SR$$=12$$cm, QM$$=7.6$$cm, PS$$=8$$cm.Area of parallelogram$$=$$base$$\times$$height$$=12\times 7.6=91.2cm^2$$.Area of parallelogram$$=$$base$$\times$$height$$\Rightarrow 91.2=8\times$$QN$$\Rightarrow QN=\dfrac{91.2}{8}=11.4$$cm.

Given: SR$$=12$$cm, QM$$=7.6$$cm, PS$$=8$$cm.

Area of parallelogram$$=$$base$$\times$$height
$$=12\times 7.6=91.2cm^2$$.

Area of parallelogram$$=$$base$$\times$$height
$$\Rightarrow 91.2=8\times$$QN
$$\Rightarrow QN=\dfrac{91.2}{8}=11.4$$cm.