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Question

Pressure P varies as P=αβ exp(αKBθZ) where Z denotes distance,KB Boltzman's constant,θ absolute temperature and α,β are constants.Derive the dimensions of β
  1. [M0L0T0]
  2. [M0L2T0]
  3. [M1LT2]
  4. [M0L1T2]

A
[M0L0T0]
B
[M0L2T0]
C
[M1LT2]
D
[M0L1T2]
Solution
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P=αβ exp(αkBθZ)
Since the terms inside the exponential do not have any dimension,we can find out the dimension of α
α×L×kJ×k
α has dimension of JL=ML2T2L=MLT2
For αβ to have dimension of pressure ,i.e ML1T2
β should have the dimension L2 i.e,M0L2T0

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