Propane cannot be prepared from which reaction-

Question

Toppr Admin · Accepted Answer

Correct option is A- -CH-3 - CH - CH-2 -xrightarrow-OH-B-2H-6-Hydroboration of alkanes followed by hydrolysis in basic medium yield alcohols and not the alkanes-R - CH - CH-2 -xrightarrow-B-2H-6- -R - CH-2 - CH-2-3 - B -xrightarrow-OH- R - CH-2 - CH-2OH-

Propane cannot be prepared from which reaction?

Correct option is A. $$CH_3 - CH = CH_2 \xrightarrow[OH^-]{B_2H_6}$$
Hydroboration of alkanes followed by hydrolysis in basic medium yield alcohols and not the alkanes.

$$R - CH = CH_2 \xrightarrow[]{B_2H_6} (R - CH_2 - CH_2)_3 - B \xrightarrow[]{OH^-} R - CH_2 - CH_2OH$$

Propane cannot be prepared from which reaction?

Correct option is A. $$CH_3 - CH = CH_2 \xrightarrow[OH^-]{B_2H_6}$$Hydroboration of alkanes followed by hydrolysis in basic medium yield alcohols and not the alkanes.$$R - CH = CH_2 \xrightarrow[]{B_2H_6} (R - CH_2 - CH_2)_3 - B \xrightarrow[]{OH^-} R - CH_2 - CH_2OH$$

Correct option is A. $$CH_3 - CH = CH_2 \xrightarrow[OH^-]{B_2H_6}$$
Hydroboration of alkanes followed by hydrolysis in basic medium yield alcohols and not the alkanes.

$$R - CH = CH_2 \xrightarrow[]{B_2H_6} (R - CH_2 - CH_2)_3 - B \xrightarrow[]{OH^-} R - CH_2 - CH_2OH$$