Prove that ABC is an isosceles triangle. APPB=AQQC and ∠APQ=∠ACB
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Q2
In the adjacent figure △ABC is isosceles as ¯¯¯¯¯¯¯¯AB=¯¯¯¯¯¯¯¯AC,¯¯¯¯¯¯¯¯BA and ¯¯¯¯¯¯¯¯CA are produced to Q and P such that ¯¯¯¯¯¯¯¯AQ=¯¯¯¯¯¯¯¯AP. Show that ¯¯¯¯¯¯¯¯PB=¯¯¯¯¯¯¯¯¯QC
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Q3
ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP=1 cm, PB=3 cm, AQ=1.5 cm, QC=4.5 m, prove that area of △APQ is one- sixteenth of the area of △ABC.
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Q4
In ΔABC, ∠A is obtuse, PB⊥AC and QC⊥AB. Prove that AB×AQ=AC×AP.
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Q5
In the given figure, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, PB = 3 cm, AQ = 1.5 cm, QC = 4.5 cm, prove that are of ∆APQ is of the area of ∆ABC.