Prove that angle B - angle C

Question

Prove that  angle B - angle C

Toppr Admin · Accepted Answer

From the figure-160-160- BD - CD -160-In - -Delta ABD - and - -Delta ACD -160- BD - CD -160- AD - AD - is common-160-angle ADB-angle ADC-90-o- -Delta ABD -equiv -Delta ACD - -SAS Axiom-160-angle B-angle C-160- -c-p-c-t-Therefore - it is proved-

Prove that
$$ \angle B = \angle C $$

From the figure
$$ BD = CD $$
In $$ \Delta ABD $$ and $$ \Delta ACD $$
$$ BD = CD $$
$$ AD = AD $$ is common
$$\angle ADB=\angle ADC=90^o$$
$$ \Delta ABD \equiv \Delta ACD $$ (SAS Axiom)
$$\angle B=\angle C$$ (c.p.c.t)
Therefore , it is proved.

Prove that $$ \angle B = \angle C $$

From the figure $$ BD = CD $$ In $$ \Delta ABD $$ and $$ \Delta ACD $$ $$ BD = CD $$ $$ AD = AD $$ is common $$\angle ADB=\angle ADC=90^o$$$$ \Delta ABD \equiv \Delta ACD $$ (SAS Axiom) $$\angle B=\angle C$$ (c.p.c.t)Therefore , it is proved.

Prove that
$$ \angle B = \angle C $$

From the figure
$$ BD = CD $$
In $$ \Delta ABD $$ and $$ \Delta ACD $$
$$ BD = CD $$
$$ AD = AD $$ is common
$$\angle ADB=\angle ADC=90^o$$
$$ \Delta ABD \equiv \Delta ACD $$ (SAS Axiom)
$$\angle B=\angle C$$ (c.p.c.t)
Therefore , it is proved.