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Question

Prove that he expression (1+m)+i(1m)(1+m)i(1m)(1m)+i(1+m)(1m)i(1+m)(mR) simplifies to 2m.

Solution
Verified by Toppr

rationalise numerator and denominator in both the terms of expression.
on rationalisation we get.
((1+m)+i(1m))22((1m)+i(1+m))22
=(1+m1+m+2i(1+m)(1m))(1m1m+2i(1+m)(1m))2
=2m

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