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Question

Prove that n2+n is divisible by 2 for any positive integer n.

Solution
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Let m=n2+n=n(n+1)

Clearly seen, the m is product of two consecutive
integers. i.e. our even and one odd

when dividing from 2 it will be divisible because
there is always an even team preset.

No2=n(n+1)2= of integers from 0 to

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