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Standard XI
Mathematics
NCERT
Question
Prove that:
2
s
i
n
2
3
π
4
+
2
c
o
s
2
π
4
+
2
s
e
c
2
π
3
=
10
Open in App
Solution
Verified by Toppr
L
H
S
=
2
s
i
n
2
3
π
4
+
2
c
o
s
2
π
4
+
2
s
e
c
2
π
3
=
2
sin
2
(
π
−
π
4
)
+
2
(
1
√
2
)
2
+
2
(
2
)
2
=
2
(
1
√
2
)
2
+
1
+
8
=
10
=
R
H
S
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Similar Questions
Q1
Prove that:
2
s
i
n
2
3
π
4
+
2
c
o
s
2
π
4
+
2
s
e
c
2
π
3
=
10
View Solution
Q2
Prove that :
2
sin
2
3
π
4
+
2
cos
2
π
4
+
2
sec
2
π
3
=
10
View Solution
Q3
2
sin
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3
π
4
+
2
cos
2
π
4
+
2
sec
2
π
3
=
10
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Q4
Prove that :
1
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sin
x
=
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(
π
4
−
x
2
)
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Q5
G
i
v
e
n
t
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a
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w
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View Solution