Prove the following:
cos(π4−x)cos(π4−y)−sin(π4−x)sin(π4−y)=sin(x+y)
LHS=cos(π4−x)cos(π4−y)−sin(π4−x)sin(π4−y)=cos(π4−x+π4−y)Using identity cosAcosB−sinAsinB=cos(A+B)
=cos(π2−(x+y))=sin(x+y)=RHS
∴cos(π4−x)cos(π4−y)−sin(π4−x)sin(π4−y)=sin(x+y)
Hence proved