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Question

Quantum number ( $n = 3$ ) has:
s, p electrons
s electrons
s, p, d, electrons
s,p,d,f electrons

A

s, p electrons

B

s, p, d, electrons

C

s electrons

D

s,p,d,f electrons

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Solution

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For a principal quantum number, n,
$0 \leq l < n$ .
Therefore, for $n = 3, l = 0, 1, 2$ .

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