Question

Radiation of wavelength $\lambda$, is incident on a photocell. The fastest emitted electron has speed $v$. If the wavelength is changed to $\frac{3\lambda }{4}$, the speed of the fastest emitted electron will be

• A. $>v{\left(\frac{4}{3}\right)}^{1/2}$
• B. $<v{\left(\frac{4}{3}\right)}^{1/2}$
• C. $=v{\left(\frac{4}{3}\right)}^{1/2}$
• D. $=v{\left(\frac{3}{4}\right)}^{1/2}$

Answer 1

Answer: (C)