Rakesh has a rectangular field of length $$80\ \text{m}$$ and breadth $$60\ \text{m}$$. In it, he wants to make a garden $$10\ \text{m}$$ long and $$4\ \text{m}$$ broad at one of the corners and at another corner, he wants to grow flowers in two floor-beds each of size $$4\ \text{m}$$ by $$1.5\ \text{m}$$. In the remaining part of the field, he wants to apply manures. Find the cost of applying the manure at the rate of $$\text{Rs}\ 300/\text{m}^2 $$.
Area of rectangular field $$=80 \times 60=4800 \text{ m}^2$$
Area of garden$$=10\times 4=40\text{ m}^2$$
Area of two flower-beds $$=2(4\times 1.5)=12\text{ m}^2$$
Area of the remaining field $$=4800-40-12=4748 \text{ m}^2$$
$$\because$$ Cost of applying manure in $$1\text{ m}^2$$ $$=\text{Rs }30$$
$$\therefore$$ Cost of applying manure in $$4748\text{ m}^2=4748\times 30=\text{Rs }1,42,440$$