Ratan travelled 300 km in 20 hours- He covered 3-5th of the distance in 2-5th of the time- At what speed did he cover the remaining distance - 10121571-2

Question

Toppr Admin · Accepted Answer

35 of 300-180 kms in-xA0-25 of 20 hrs -8 hrsSo remaining 120 kms in 12 hrsspeed-xA0-12012-10 km-hr

Ratan travelled $300 k m$ in $20$ hours. He covered $3 / 5 t h$ of the distance in $2 / 5 t h$ of the time. At what speed did he cover the remaining distance ?
$10$
$12$
$15$
$71 / 2$

$\frac{3}{5}$ of $300 = 180$ kms in $\frac{2}{5}$ of $20$ hrs $= 8$ hrs
So remaining $120$ kms in $12$ hrs
speed $= \frac{120}{12} = 10$ km/hr

Ratan travelled 300 km in 20 hours. He covered 3/5th of the distance in 2/5th of the time. At what speed did he cover the remaining distance ? 10121571/2

35 of 300=180 kms in 25 of 20 hrs =8 hrsSo remaining 120 kms in 12 hrsspeed =12012=10 km/hr

Ratan travelled $300 k m$ in $20$ hours. He covered $3 / 5 t h$ of the distance in $2 / 5 t h$ of the time. At what speed did he cover the remaining distance ?
$10$
$12$
$15$
$71 / 2$

$\frac{3}{5}$ of $300 = 180$ kms in $\frac{2}{5}$ of $20$ hrs $= 8$ hrs
So remaining $120$ kms in $12$ hrs
speed $= \frac{120}{12} = 10$ km/hr