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Mutual Induction

Question

Ratio of the currents $I_{1}$ and $I_{2}$ flowing through the circular and straight parts is

A

\frac{\sqrt{3}}{2 π}

B

\frac{2 \sqrt{3}}{π}

C

\frac{3 \sqrt{3}}{2 π}

D

\frac{3 \sqrt{3}}{2 \sqrt{2} π}

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Solution

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If $I_{1}$ and $I_{2}$ be the currents in circular and straight parts, respectively, and $B_{1}$ and $B_{2}$ the magnetic fiels due to them, then

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