Reaction in which exactly two carbons are oxidized ?
Reaction of Pentan-3-one with $C H_{3} C O_{3} H$
Reaction of acetone with NAOH/ $I_{2}$
Reaction of propene with $B r_{2}$
Reaction of $(C H_{3})_{2}$ $(C H_{3})_{2} C$ = NOH with $H_{2} S o_{4}$

Question

Reaction in which exactly two carbons are oxidized ?
Reaction of Pentan-3-one with $C H_{3} C O_{3} H$
Reaction of acetone with NAOH/ $I_{2}$
Reaction of propene with $B r_{2}$
Reaction of $(C H_{3})_{2}$ $(C H_{3})_{2} C$ = NOH with $H_{2} S o_{4}$

Toppr Admin · Accepted Answer

CH3COCH34NaOH3I2-x2192-CHI3-3NaS-xA0-Acetone-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0-CH3COONa-3H2O-xA0-two carbons are oxidised in this reaction -xA0-so- Reaction of acetone with NAOH-xA0-I2-xA0-is correct answer-xA0-

	Column I		Column II
(A)	Hydrazine	(i)	$(C H_{3})_{2} C = N N H C O N H_{2}$
(B)	Semicarbazide	(ii)	$(C H_{3})_{2} C = N O H$
(C)	Phenylhydrazine	(iii)	$(C H_{3})_{2} C = N N H_{2}$
(D)	Hydroxylamine	(iv)	$(C H_{3})_{2} C = N N H C_{6} H_{5}$

Reaction in which exactly two carbons are oxidized ?Reaction of Pentan-3-one with CH3CO3HReaction of acetone with NAOH/I2Reaction of propene with Br2Reaction of (CH3)2(CH3)2C= NOH with H2So4

CH3COCH34NaOH3I2→CHI3+3NaS+ Acetone CH3COONa+3H2O two carbons are oxidised in this reaction . so, Reaction of acetone with NAOH /I2 is correct answer.

Reaction in which exactly two carbons are oxidized ?
Reaction of Pentan-3-one with $C H_{3} C O_{3} H$
Reaction of acetone with NAOH/ $I_{2}$
Reaction of propene with $B r_{2}$
Reaction of $(C H_{3})_{2}$ $(C H_{3})_{2} C$ = NOH with $H_{2} S o_{4}$

${C H}_{3} {C O C H}_{3} \frac{4 N a O H}{3 I_{2}} \to {C H I}_{3} + 3 N a S +$
Acetone ${C H}_{3} C O O N a + 3 H_{2} O$
$\begin{matrix} two carbons are oxidised in this reaction . so, Reaction of acetone with NAOH / I_{2} is correct answer. \end{matrix}$