Reaction of water to an acid is- H - 2 -O-4- SO - 2 -2- O - 2 -rightarrow - H - 2 - SO - 4 - 4H - 2 -O-4- SO - 2 -3- O - 2 -rightarrow - 4H - 2 - SO - 4 - 4H - 2 -O-4- SO - 2 -2- O - 2 -rightarrow - 4H - 2 - SO - 4 - 5H - 2 -O-4- SO - 2 - O - 2 -rightarrow - 4H - 2 - SO - 4 -H-2

Question

Toppr Admin · Accepted Answer

Water reacts with SO2 to converted into sulphuric acid as-I- 2SO2-O2-x2192-2SO3II- 2H2O-2SO3-x2192-H2SO4Net reaction-2H2O-2SO2-O2-x2192-2H2SO4-xA0-quot-or-quot-4H2O-4SO2-2O2-x2192-4H2SO4

Reaction of water to an acid is:
$H_{2} O + 4 {S O}_{2} + 2 O_{2} \to H_{2} {S O}_{4}$
${4 H}_{2} O + 4 {S O}_{2} + 3 O_{2} \to {4 H}_{2} {S O}_{4}$
${4 H}_{2} O + 4 {S O}_{2} + 2 O_{2} \to {4 H}_{2} {S O}_{4}$
${5 H}_{2} O + 4 {S O}_{2} + O_{2} \to {4 H}_{2} {S O}_{4} + H_{2}$

Water reacts with $S O_{2}$ to converted into sulphuric acid as:

I: $2 S O_{2} + O_{2} \to 2 S O_{3}$

II: $2 H_{2} O + 2 S O_{3} \to H_{2} S O_{4}$

Net reaction:
${2 H}_{2} O + 2 {S O}_{2} + O_{2} \to {2 H}_{2} {S O}_{4}$

"or"

${4 H}_{2} O + 4 {S O}_{2} + 2 O_{2} \to {4 H}_{2} {S O}_{4}$

Reaction of water to an acid is:H2O+4SO2+2O2→H2SO44H2O+4SO2+3O2→4H2SO44H2O+4SO2+2O2→4H2SO45H2O+4SO2+O2→4H2SO4+H2

Water reacts with SO2 to converted into sulphuric acid as:I: 2SO2+O2→2SO3II: 2H2O+2SO3→H2SO4Net reaction:2H2O+2SO2+O2→2H2SO4 "or"4H2O+4SO2+2O2→4H2SO4

Reaction of water to an acid is:
$H_{2} O + 4 {S O}_{2} + 2 O_{2} \to H_{2} {S O}_{4}$
${4 H}_{2} O + 4 {S O}_{2} + 3 O_{2} \to {4 H}_{2} {S O}_{4}$
${4 H}_{2} O + 4 {S O}_{2} + 2 O_{2} \to {4 H}_{2} {S O}_{4}$
${5 H}_{2} O + 4 {S O}_{2} + O_{2} \to {4 H}_{2} {S O}_{4} + H_{2}$

Water reacts with $S O_{2}$ to converted into sulphuric acid as:

I: $2 S O_{2} + O_{2} \to 2 S O_{3}$

II: $2 H_{2} O + 2 S O_{3} \to H_{2} S O_{4}$

Net reaction:
${2 H}_{2} O + 2 {S O}_{2} + O_{2} \to {2 H}_{2} {S O}_{4}$

"or"

${4 H}_{2} O + 4 {S O}_{2} + 2 O_{2} \to {4 H}_{2} {S O}_{4}$