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Question

Reduce the following fractions to simplest form :
$$(i)\ \dfrac{12}{27}\\(ii)\ \dfrac{150}{350}\\(iii)\ \dfrac{18}{81} \\ (iv)\ \dfrac{276}{115}$$

Solution
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To reduce a fraction to its simplest form, we divide the numerator and denominator by their LCM.
$$(i)\ \dfrac{12}{27} = \dfrac{12 \div 3}{27 \div 3} = \dfrac{4}{9}\\(ii)\ \dfrac{150}{350} = \dfrac{150 \div 50}{350 \div 50} = \dfrac{3}{7}\\ (iii)\ \dfrac{18}{81} = \dfrac{18 \div 9}{81 \div 9} = \dfrac{12}{5}\\ (iv)\ \dfrac{276}{115} = \dfrac{276 \div 23}{115 \div 23} = \dfrac{12}{5}$$

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