Reena has enough money to buy 10 kg of potatoes worth Rs 18-kg with the same money- How much kilograms of potatoes can she buy the price of potatoes increases to Rs 20-kg

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Que- Reena has money to buy 10 kg potatoes at rateRs 18-kg-x2192-Money-10-xD7-18180Rs-x2192- at rate 20 Rs-kg-xA0-Money - rate -xD7- weight180-20-xD7- weight-xA0-weight -18020- 9 kg-xA0-Reena buy 9 kg of potatoes If price increase to 20-kg-

Reena has enough money to buy $10 k g$ of potatoes worth $R s 18 / k g$ with the same money. How much kilograms of potatoes can she buy if the price of potatoes increases to $R s 20 / k g$

Que. Reena has money to buy 10 kg potatoes at rate
Rs 18/kg.
$\to M o n e y = 10 \times 18$
$180 R s .$
$\to$ at rate 20 Rs/kg.
Money = rate $\times$ weight
$180 = 20 \times$ weight
weight $= \frac{180}{20}$
= 9 kg
Reena buy 9 kg of potatoes If price increase to 20/kg.

Reena has enough money to buy 10 kg of potatoes worth Rs 18/kg with the same money. How much kilograms of potatoes can she buy if the price of potatoes increases to Rs 20/kg

Que. Reena has money to buy 10 kg potatoes at rateRs 18/kg.→Money=10×18180Rs.→ at rate 20 Rs/kg. Money = rate × weight180=20× weight weight =18020= 9 kg Reena buy 9 kg of potatoes If price increase to 20/kg.

Reena has enough money to buy $10 k g$ of potatoes worth $R s 18 / k g$ with the same money. How much kilograms of potatoes can she buy if the price of potatoes increases to $R s 20 / k g$

Que. Reena has money to buy 10 kg potatoes at rate
Rs 18/kg.
$\to M o n e y = 10 \times 18$
$180 R s .$
$\to$ at rate 20 Rs/kg.
Money = rate $\times$ weight
$180 = 20 \times$ weight
weight $= \frac{180}{20}$
= 9 kg
Reena buy 9 kg of potatoes If price increase to 20/kg.