Refer to teh circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_{1}$ ? It is given that $R_{2} = 4 R_{1}$ and $R_{3} = 12 R_{1}$

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Answer 1

Total equivalent resistance= $\frac{R _{2} R _{3}}{R _{2} + R _{3}} + R_{1} = \frac{4 8 R _{1} ^{2}}{1 6 R _{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}$
Power dissipation at $R_{1} = I^{2} R_{1} = P$
$∴$ Power dissipation in the total circuit= $I^{2} 4 R_{1}$
$= 4 I^{2} R_{1}$
$= 4 P$

Answer 2

Total equivalent resistance=

\frac{R _{2} R _{3}}{R _{2} + R _{3}} + R_{1} = \frac{4 8 R _{1} ^{2}}{1 6 R _{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}

Power dissipation at

R_{1} = I^{2} R_{1} = P

∴

Power dissipation in the total circuit=

I^{2} 4 R_{1}

= 4 I^{2} R_{1}

= 4 P

Refer to teh circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_{1}$ ? It is given that $R_{2} = 4 R_{1}$ and $R_{3} = 12 R_{1}$

$4 P$

$7 P$

$13 P$

$17 P$

Solution

Total equivalent resistance= $\frac{R _{2} R _{3}}{R _{2} + R _{3}} + R_{1} = \frac{4 8 R _{1} ^{2}}{1 6 R _{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}$
Power dissipation at $R_{1} = I^{2} R_{1} = P$
$∴$ Power dissipation in the total circuit= $I^{2} 4 R_{1}$
$= 4 I^{2} R_{1}$
$= 4 P$

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Refer to teh circuit shown. What will be the total power dissipation in the circuit if P is the power dissipated in R1​? It is given that R2​=4R1​ and R3​=12R1​

4P

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17P

Total equivalent resistance=R2​+R3​R2​R3​​+R1​=16R1​48R1​2​+R1​=3R1​+R1​=4R1​Power dissipation at R1​=I2R1​=P∴ Power dissipation in the total circuit=I24R1​=4I2R1​=4P

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Refer to teh circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_{1}$ ? It is given that $R_{2} = 4 R_{1}$ and $R_{3} = 12 R_{1}$

$4 P$

$7 P$

$13 P$

$17 P$

Total equivalent resistance= $\frac{R _{2} R _{3}}{R _{2} + R _{3}} + R_{1} = \frac{4 8 R _{1} ^{2}}{1 6 R _{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}$
Power dissipation at $R_{1} = I^{2} R_{1} = P$
$∴$ Power dissipation in the total circuit= $I^{2} 4 R_{1}$
$= 4 I^{2} R_{1}$
$= 4 P$

The power consumed by $4$ V battery in the circuit as shown is?

Power dissipated across the $8 Ω$ resistor in the circuit shown here is $2 W$ . The power dissipated in watt units across the $3 Ω$ resistor is