Refer to teh circuit shown- What will be the total power dissipation in the circuit P is the power dissipated in -R-1- It is given that -R-2-4-R-1- and -R-3-12-R-1-4P7P13P17P

Question

Toppr Admin · Accepted Answer

Total equivalent resistance-R2R3R2-R3-R1-48R1216R1-R1-3R1-R1-4R1Power dissipation at R1-I2R1-P-x2234- Power dissipation in the total circuit-I24R1-4I2R1-4P

Refer to teh circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_{1}$ ? It is given that $R_{2} = 4 R_{1}$ and $R_{3} = 12 R_{1}$

$4 P$
$7 P$
$13 P$
$17 P$

Total equivalent resistance= $\frac{R_{2} R_{3}}{R_{2} {+ R}_{3}} + R_{1} = \frac{48 {R_{1}}^{2}}{16 R_{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}$
Power dissipation at $R_{1} = I^{2} R_{1} = P$
$∴$ Power dissipation in the total circuit= $I^{2} 4 R_{1}$
$= 4 I^{2} R_{1}$
$= 4 P$

Refer to teh circuit shown. What will be the total power dissipation in the circuit if P is the power dissipated in R1? It is given that R2=4R1 and R3=12R14P7P13P17P

Total equivalent resistance=R2R3R2+R3+R1=48R1216R1+R1=3R1+R1=4R1Power dissipation at R1=I2R1=P∴ Power dissipation in the total circuit=I24R1=4I2R1=4P

Refer to teh circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_{1}$ ? It is given that $R_{2} = 4 R_{1}$ and $R_{3} = 12 R_{1}$

$4 P$
$7 P$
$13 P$
$17 P$

Total equivalent resistance= $\frac{R_{2} R_{3}}{R_{2} {+ R}_{3}} + R_{1} = \frac{48 {R_{1}}^{2}}{16 R_{1}} + R_{1} = 3 R_{1} + R_{1} = 4 R_{1}$
Power dissipation at $R_{1} = I^{2} R_{1} = P$
$∴$ Power dissipation in the total circuit= $I^{2} 4 R_{1}$
$= 4 I^{2} R_{1}$
$= 4 P$