Referring to the given figure- E is the center of the circle and displaystyle - AC - and displaystyle- BD - are diameters- If displaystyle Delta AEB cong Delta DEC- then the congruence theorem used to prove this is-AAASSSSASSSA

Question

Referring to the given figure- E is the center of the circle and displaystyle - AC -  and displaystyle- BD -  are diameters- If displaystyle Delta AEB cong Delta DEC- then the congruence theorem used to prove this is-AAASSSSASSSA

Toppr Admin · Accepted Answer

-SAS-property-If-two sides and the included angle of one triangle are equal to the-corresponding sides and angle of another triangle- the triangles are-congruent- -In-xA0-xA0-x394-AEB and -x394-DEC-x2220-BEA-x2245-x2220-CED -xA0- -xA0- -xA0- -xA0-vertically opposite anglesside EA-x2245- side EC -xA0- -xA0- -xA0-radii of same circleside EB-x2245- side ED-xA0-xA0-xA0- -xA0-radii of same circle-xA0-x2234-x394-AEB-x2245-x394-DEC -xA0- -xA0- -xA0-S-A-S test-

Referring to the given figure, $E$ is the center of the circle and $A C$ and $B D$ are diameters. If $Δ A E B ≅ Δ D E C$ , then the congruence theorem used to prove this is:

$A A A$
$S S S$
$S A S$
$S S A$

SAS property:

Referring to the given figure, E is the center of the circle and AC and BD are diameters. If ΔAEB≅ΔDEC, then the congruence theorem used to prove this is:AAASSSSASSSA

SAS property:

Referring to the given figure, $E$ is the center of the circle and $A C$ and $B D$ are diameters. If $Δ A E B ≅ Δ D E C$ , then the congruence theorem used to prove this is:

$A A A$
$S S S$
$S A S$
$S S A$