$$Zn+CuSO_4 \to ZnSO_4 +Cu$$
The electrochemical cell of this reaction is represented as follows:
Anodic representation $$-Zn / Zn^{2}(1M)$$, which is written on the left side.
Cathodic representation $$-Cu^{2+}(1M)/Cu$$, which is written on the right sie.
Salt bridge is represented by two line between the two half reactions.
$$Zn / Zn^{2+}(1M) \ || \ Cu^{2+}(1M) /Cu$$