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Standard XII
Chemistry
EMF
Question
Represent the cell in which the following reaction takes place
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
→
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
Calculate its
E
(
c
e
l
l
)
if
E
o
(
c
e
l
l
)
=
3.17
V
Open in App
Solution
Verified by Toppr
M
g
+
2
A
g
+
(
0.0001
M
)
⟶
M
g
2
+
(
0.130
M
)
+
2
A
g
E
c
e
l
l
=
E
o
−
0.0591
2
log
[
(
M
g
2
+
)
(
A
g
+
)
2
]
E
c
e
l
l
=
8.17
−
0.0591
2
log
[
0.130
10
−
8
]
=
2.959
V
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Similar Questions
Q1
Represent the cell in which the following reaction takes place
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
→
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
Calculate its
E
(
c
e
l
l
)
if
E
o
(
c
e
l
l
)
=
3.17
V
View Solution
Q2
The following reactions occurs in the cell
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
⇌
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
. Calculate
E
(
c
e
l
l
)
E
0
(
c
e
l
l
)
=
3.17
v
o
l
t
View Solution
Q3
A cell in which the following reaction takes place:-
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
→
M
g
+
2
(
0.120
M
)
+
2
A
g
(
s
)
if
E
∘
c
e
l
l
=
3.17
v
o
l
t
then calculate
E
c
e
l
l
View Solution
Q4
Mg in the solid state
(
M
g
(
s
)
)
+
2
A
g
+
(
0.001
M
)
→
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
represent the cell. Calculate the emf of the cell at
298
K.
Given:
E
o
c
e
l
l
=
3.17
V.
View Solution
Q5
Answer the following questions:
a) Calculate the EMF of the cell for the reaction
M
g
(
s
)
+
2
A
g
+
(
a
q
)
→
M
g
2
+
(
a
q
)
+
2
A
g
(
s
)
.
Given :
E
0
M
g
2
+
/
M
g
=
−
2.37
V
E
0
A
g
+
/
A
g
=
0.80
V
[
M
g
2
+
]
=
0.001
M
;
[
A
g
+
]
=
0.0001
M
b) What are fuel cells?
View Solution