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Question

Represent the following mixed infinite decimal periodic fractions as common fractions:
2(a+b)1(ab)1/21+14(abba)21/2

Solution
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2(a+b)1(ab)12(1+14(abba)2)12
=2(a+b)1ab(4ab+(ab)2)12(4ab)12
=2(a+b)1ab((a+b)2)122ab
=(a+b)1(a+b)=1

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