Restate the following statements with appropriate conditions, so that they become true statements.
For any $x, 3 x + 1 > 4$ .

Question

Restate the following statements with appropriate conditions- so that they become true statements-For any x- x-3geq 0-

Toppr Admin · Accepted Answer

If-xA0-x-x2265-0 then -xA0-x3-x2265-0 the statement -xA0-becomes truethis can be verified as follows-xA0-If -xA0-x-0 then -xA0-x3-0-xA0-If-xA0-x-1Then -xA0-x3-1If -xA0-x-2 -xA0-then x3-8hence-x3-gt-0 only if x-gt-0

Restate the following statements with appropriate conditions, so that they become true statements.
For any $x, x^{3} \geq 0$ .

If $x \geq 0$ then $x^{3} \geq 0$ the statement becomes true
this can be verified as follows,
If $x = 0$ then $x^{3} = 0$
If $x = 1$ Then $x^{3} = 1$
If $x = 2$ then $x^{3} = 8$
hence, $x^{3} > 0$ only if $x > 0$

Restate the following statements with appropriate conditions, so that they become true statements.For any x,x3≥0.

If x≥0 then x3≥0 the statement becomes truethis can be verified as follows, If x=0 then x3=0 If x=1Then x3=1If x=2 then x3=8hence,x3>0 only if x>0

Restate the following statements with appropriate conditions, so that they become true statements.
For any $x, x^{3} \geq 0$ .

If $x \geq 0$ then $x^{3} \geq 0$ the statement becomes true
this can be verified as follows,
If $x = 0$ then $x^{3} = 0$
If $x = 1$ Then $x^{3} = 1$
If $x = 2$ then $x^{3} = 8$
hence, $x^{3} > 0$ only if $x > 0$