Select correct alternates-s-In KHCO-3- the HC- O - 3 - - - ions are linked into infinite chainIn KHCO-3- a dimer is formed by H-bondingIn NaHCO-3- a dimer is formed by H-bondingIn NaHCO-3- the HC- O - 3 - - - ions are linked into infinite chain

Question

Toppr Admin · Accepted Answer

In NaHCO3- the HCO-x2212-3 ions are linked into an infinite chain and -B- in KHCO3-HCO-x2212-3 forms a dimeric anion-

Select correct alternates(s).
In $K H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into infinite chain
In $K H C O_{3}$ , a dimer is formed by H-bonding
In $N a H C O_{3}$ , a dimer is formed by H-bonding
In $N a H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into infinite chain

In $N a H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into an infinite chain and $(B)$ in $K H C O_{3}, H C O_{3}^{-}$ forms a dimeric anion.

Select correct alternates(s).In KHCO3, the HCO−3 ions are linked into infinite chainIn KHCO3, a dimer is formed by H-bondingIn NaHCO3, a dimer is formed by H-bondingIn NaHCO3, the HCO−3 ions are linked into infinite chain

In NaHCO3, the HCO−3 ions are linked into an infinite chain and (B) in KHCO3,HCO−3 forms a dimeric anion.

Select correct alternates(s).
In $K H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into infinite chain
In $K H C O_{3}$ , a dimer is formed by H-bonding
In $N a H C O_{3}$ , a dimer is formed by H-bonding
In $N a H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into infinite chain

In $N a H C O_{3}$ , the $H C O_{3}^{-}$ ions are linked into an infinite chain and $(B)$ in $K H C O_{3}, H C O_{3}^{-}$ forms a dimeric anion.