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Question

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Statement -1 : Two thin lenses of power + 4D and - 2D are in contact. The focal length of the combination is 50 cm.
Statement -2 : The maximum kinetic energy of a photoelectron is 3 eV then stopping potential must be less than 3V.
Statement -3 :When a charge particle is released in uniform magnetic field it may perform circular motion due to magnetic force.
  1. FFF
  2. TFT
  3. TFF
  4. TTT

A
TFT
B
FFF
C
TFF
D
TTT
Solution
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Statement 1: If P1 and P2 are the power of lenses of focal length F1 and F2 respectively , then focal length of the combination is 1/F=P1+P2.
Statement 2: Stopping potential =( maximum kinetic energy)/ e.
Statement 3: F=q(v×B) , Where F is force, q is charge of particle , v is velocity of particle and B is magnetic field . If v =0, then F=0 , so no circular motion takes place

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