Question

Simplify: $$[8(5/6)]-[3(3/8)]+[1(7/12)]$$

Answer 1

First we convert each mixed fraction into an improper fraction.
$$\Rightarrow [8(5/6)]=(53/6)$$
also $$\Rightarrow [3(3/8)]=(27/8)$$

and $$\Rightarrow [1(7/12)]=(19/12)$$

Then,
$$(53/6)-(27-8)-(19/12)$$
LCM of $$6,8,12=24$$
Now, let us change each of the given fraction into an equivalent fraction having $$24 $$ as the denominator.
$$=[(53/6)\times(4/4)]=(212/24)$$
also $$=[(27/8)\times (3/3)]=(81/24)$$

and $$=[(19/12)\times(2/2)]=(38/24)$$

Now,
$$=(212/24)-(81/24)-(38/24)$$
$$=[(212-81+38)/24]$$
$$=[(250-81/24)]$$
$$=(169/24)$$
$$=[7(1/24)]$$