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Question

Simplify and write the following exponential form:
$$((-2)^3)^2 +5^{-3}\div 5^{-5}-(-1/2)^0$$

Solution
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$$((-2)^3)^2 +5^{-3}\div 5^{-5}-(-1/2)^0$$
Let us simplify,
$$((-2)^3)^2 +5^{-3}\div 5^{-5}-(-1/2)^0 = (-2)^6 +1/5^3 \div 1/5^5 -1$$
$$=64+1/5^3 \times 5^5 -1$$
$$=64+5^{5-3}-1$$
$$=64+5^2 -1$$
$$=64+25-1$$
$$=88$$
The exponential form is $$88$$.

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