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Question

$s i n 60^{\circ} = 2 s i n 30^{\circ} c o s 30^{\circ}$
If true then write 1 and if false then write 0.

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Solution

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To Prove: $sin 60^{0} = 2 sin 30^{0} cos 30^{0}$
L.H.S.: $s i n 60^{\circ} = \frac{\sqrt{3}}{2}$
R.H.S.: $2 sin 30^{\circ} cos 30^{\circ} = 2 \times \frac{1}{2} \times \frac{\sqrt{3}}{2} = \frac{\sqrt{3}}{2}$
Thus, $L . H . S . = R . H . S$

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