Six boys and girls sit in a row randomly. Find the probability that the six girls sit together.
$p = \frac{1}{66}$
$p = \frac{1}{924}$
$p = \frac{1}{132}$
$p = \frac{1}{95040}$

Question

Six boys and girls sit in a row randomly- Find the probability that the six girls sit together-p-displaystyle frac-1-66-p-displaystyle frac-1-924-p-displaystyle frac-1-132-p-displaystyle frac-1-95040-

Toppr Admin · Accepted Answer

Total number of boys and girls -6-6-12Total cases -12-

Six boys and girls sit in a row randomly. Find the probability that the six girls sit together.p=166p=1924p=1132p=195040

Total number of boys and girls =6+6=12Total cases =12!

Six boys and girls sit in a row randomly. Find the probability that the six girls sit together.
$p = \frac{1}{66}$
$p = \frac{1}{924}$
$p = \frac{1}{132}$
$p = \frac{1}{95040}$

Total number of boys and girls $= 6 + 6 = 12$
Total cases $= 12!$