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Six charges are placed at the corner of a regular hexagon as shown. If an electron is placed at the centre O, force on it will be:
- zero
- along OF
- along OC
- none of these
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Solution
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The charges will be balanced by their counterparts on opposite side. So eventually the charges remaining will be 2q on B and 3q on D.
Since the charge distribution is unsymmetrical, the net force on charge would be skewed towards D.
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