Six particles each of mass m are placed the corners of a regular hexagon of edge length a- If a point mass m-0- is placed the centre of the hexagon- then the net gravitational force on the point mass m-0- isdfrac-6Gm-2-a-2-dfrac-6Gmm-0-a-2-zeronone of these

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Toppr Admin · Accepted Answer

The force exerted by-xA0-each particle placed on the vertices- over the particle at the-xA0-centre are equal in magnitude and cancel each other vectorially- Thus the resultant force on it is-xA0-equal to zero-

Six particles each of mass $m$ are placed at the corners of a regular hexagon of edge length $a$ . If a point mass $m_{0}$ is placed at the centre of the hexagon, then the net gravitational force on the point mass $m_{0}$ is
$\frac{6 G m^{2}}{a^{2}}$
$\frac{6 G m m_{0}}{a^{2}}$
zero
none of these

The force exerted by each particle placed on the vertices, over the particle at the centre are equal in magnitude and cancel each other vectorially. Thus the resultant force on it is equal to zero.

Six particles each of mass m are placed at the corners of a regular hexagon of edge length a. If a point mass m0 is placed at the centre of the hexagon, then the net gravitational force on the point mass m0 is6Gm2a26Gmm0a2zeronone of these

The force exerted by each particle placed on the vertices, over the particle at the centre are equal in magnitude and cancel each other vectorially. Thus the resultant force on it is equal to zero.

Six particles each of mass $m$ are placed at the corners of a regular hexagon of edge length $a$ . If a point mass $m_{0}$ is placed at the centre of the hexagon, then the net gravitational force on the point mass $m_{0}$ is
$\frac{6 G m^{2}}{a^{2}}$
$\frac{6 G m m_{0}}{a^{2}}$
zero
none of these