Sixteen cylindrical cans each with a radius of $1$ unit are placed inside a cardboard box four in a row. If the cans touch the adjacent cans and or the walls of the box, then which of the following could be the interior area of the bottom of the box in square units?

Question

Sixteen cylindrical cans each with a radius of

1

unit are placed inside a cardboard box four in a row. If the cans touch the adjacent cans and or the walls of the box, then which of the following could be the interior area of the bottom of the box in square units?

Toppr Admin · Accepted Answer

Diameter of each can -2Since- four cans are placed along the length and breadth-Length - Breadth -4-2-8 unitsThus- area of the bottom of the box - Length -xD7- Breadth -8-xD7-8-64 sq- units

Sixteen cylindrical cans each with a radius of $1$ unit are placed inside a cardboard box four in a row. If the cans touch the adjacent cans and or the walls of the box, then which of the following could be the interior area of the bottom of the box in square units?
$16$
$32$
$64$
$128$

Diameter of each can $= 2$
Since, four cans are placed along the length and breadth,
Length $=$ Breadth $= 4 (2) = 8$ units
Thus, area of the bottom of the box $=$ Length $\times$ Breadth $= 8 \times 8 = 64$ sq. units

Sixteen cylindrical cans each with a radius of 1 unit are placed inside a cardboard box four in a row. If the cans touch the adjacent cans and or the walls of the box, then which of the following could be the interior area of the bottom of the box in square units?163264128

Diameter of each can =2Since, four cans are placed along the length and breadth,Length = Breadth =4(2)=8 unitsThus, area of the bottom of the box = Length × Breadth =8×8=64 sq. units

Sixteen cylindrical cans each with a radius of $1$ unit are placed inside a cardboard box four in a row. If the cans touch the adjacent cans and or the walls of the box, then which of the following could be the interior area of the bottom of the box in square units?
$16$
$32$
$64$
$128$

Diameter of each can $= 2$
Since, four cans are placed along the length and breadth,
Length $=$ Breadth $= 4 (2) = 8$ units
Thus, area of the bottom of the box $=$ Length $\times$ Breadth $= 8 \times 8 = 64$ sq. units